軟糖來回答吧,vb.net用循環(huán)是這樣的
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dim k = new integer(9) {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
dim 和 as integer
for i = 0 to k.count - 1
和 += k(i)
next計算數(shù)組中各元素之和更簡單的方法是
使用擴展方法sum或者lambda表達式,以下兩種均可
dim 和1 = k.sum()
dim 和2 = k.aggregate(function(m, n) m + n)
'假設(shè)數(shù)組如下
dim d(10) as integer
dim i as integer
for i=lbound(d) to ubound(d)
d(i) = i
next i
'數(shù)組各元素之和
dim S as integer = 0
for i=lbound(d) to ubound(d)
s = s + d(i)
next i
msgbox(s)
Private Sub Command1_Click()
MsgBox CalcResult(2)
End Sub
Public Function CalcResult(X As Long) As Double
Dim dblMinLevel As Double
Dim dblItem As Double
Dim dblN As Double
Dim dblMember As Double, dblBase As Double
Dim i As Double
Dim dblResult As Double
dblMinLevel = 10 ^ (-6)
dblN = 0
Do
dblMember = X ^ dblN
dblBase = 1
i = dblN
Do While i 1
dblBase = dblBase * i
i = i - 1
Loop
dblItem = dblMember / dblBase
dblResult = dblResult + dblItem
dblN = dblN + 1
Loop While dblItem = dblMinLevel
CalcResult = dblResult
End Function
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